(x+1)^2-4(x+1)+2=0

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Solution for (x+1)^2-4(x+1)+2=0 equation: 



(x+1)^2-4(x+1)+2=0

We multiply parentheses

(x+1)^2-4x-4+2=0

We add all the numbers together, and all the variables

-4x+(x+1)^2-2=0

We move all terms containing x to the left, all other terms to the right

-4x+(x+1)^2=2

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